A diatomic molecule has a dipole moment of 1.2 D. If the bond distance is 1.0 mathringA, fraction of an electronic charge on each atom is

Question

A diatomic molecule has a dipole moment of 1.2 D. If the bond distance is 1.0 mathringA, fraction of an electronic charge on each atom is (A) 0.25 (B) 0.33 (C) 0.66 (D) 0.90

Tardigrade Admin · Accepted Answer

μ=e × l e=(μ/l)=(1.2 D /1.0 mathringA)=(1.2 × 10-18 esu cm /1.0 × 10-8 cm ) =1.2 × 10-10 esu Charge on electron =4.8 × 10-10 esu Thus, fraction of charge =(1.2 × 10-10/4.8 × 10-10)=0.25

Q. A diatomic molecule has a dipole moment of $1.2 D$ . If the bond distance is $1.0 \overset{˚}{A}$ , fraction of an electronic charge on each atom is

$0.25$

$0.33$

$0.66$

$0.90$

$μ = e \times l$
$e = \frac{μ}{l} = \frac{1.2 D}{1.0 A ˚} = \frac{1.2 \times 1 0 ^{- 18} es u c m}{1.0 \times 1 0 ^{- 8} c m}$
$= 1.2 \times 1 0^{- 10} es u$
Charge on electron $= 4.8 \times 1 0^{- 10}$ esu
Thus, fraction of charge $= \frac{1.2 \times 1 0 ^{- 10}}{4.8 \times 1 0 ^{- 10}} = 0.25$

Q. A diatomic molecule has a dipole moment of 1.2D. If the bond distance is 1.0A˚, fraction of an electronic charge on each atom is

0.25

0.33

0.66

0.90