A diatomic molecule has a dipole moment of 1.2 D, if the bond distance is 1 mathringA, what percentage of electronic charge exists on each atom?

Question

A diatomic molecule has a dipole moment of 1.2 D, if the bond distance is 1 mathringA, what percentage of electronic charge exists on each atom? (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

μ= e × d ∴ e =(μ/ d )=(1.2 D /1.0 A ) =(1.2 × 10-18 esu cm /1.0 × 10-8 cm ) =1.2 × 10-10 esu Percentage of electronic charge =(1.2 × 10-10 esu /4.8 × 10-10 esu ) × 100=25 %

Q. A diatomic molecule has a dipole moment of $1.2 D$ , if the bond distance is $1 \overset{˚}{A}$ , what percentage of electronic charge exists on each atom?

$μ = e \times d$
$∴ e = \frac{μ}{d} = \frac{1.2 D}{1.0 A} = \frac{1.2 \times 1 0 ^{- 18} es u c m}{1.0 \times 1 0 ^{- 8} c m}$
$= 1.2 \times 1 0^{- 10} es u$
Percentage of electronic charge
$= \frac{1.2 \times 1 0 ^{- 10} es u}{4.8 \times 1 0 ^{- 10} es u} \times 100 = 25%$

Q. A diatomic molecule has a dipole moment of 1.2D, if the bond distance is 1A˚, what percentage of electronic charge exists on each atom?

μ=e×d ∴e=dμ​=1.0A1.2D​=1.0×10−8cm1.2×10−18esucm​ =1.2×10−10esu Percentage of electronic charge =4.8×10−10esu1.2×10−10esu​×100=25%

Q. A diatomic molecule has a dipole moment of $1.2 D$ , if the bond distance is $1 \overset{˚}{A}$ , what percentage of electronic charge exists on each atom?

$μ = e \times d$
$∴ e = \frac{μ}{d} = \frac{1.2 D}{1.0 A} = \frac{1.2 \times 1 0 ^{- 18} es u c m}{1.0 \times 1 0 ^{- 8} c m}$
$= 1.2 \times 1 0^{- 10} es u$
Percentage of electronic charge
$= \frac{1.2 \times 1 0 ^{- 10} es u}{4.8 \times 1 0 ^{- 10} es u} \times 100 = 25%$