A diatomic ideal gas initially at 273 K is given 100 cal heat due to which system did 209 J work. Molar heat capacity (Cm) of gas for the process is :

Question

A diatomic ideal gas initially at 273 K is given 100 cal heat due to which system did 209 J work. Molar heat capacity (Cm) of gas for the process is : (A) (3/2) R (B) (5/2) R (C) (5/4) R (D) 5 R

Tardigrade Admin · Accepted Answer

Δ U =100-(209/4.18)=50 cal Δ U = nC v dT C v , m =(5/2) R ndT =(20/ R ) q = nC m dT C m =(100 R /20)=5 R

Q. A diatomic ideal gas initially at $273 K$ is given $100 c a l$ heat due to which system did $209 J$ work. Molar heat capacity $(C_{m})$ of gas for the process is :

$\frac{3}{2} R$

$\frac{5}{2} R$

$\frac{5}{4} R$

$5 R$

$Δ U = 100 - \frac{209}{4.18} = 50 c a l$
$Δ U = n C_{v} d T$
$C_{v, m} = \frac{5}{2} R$
$n d T = \frac{20}{R}$
$q = n C_{m} d T$
$C_{m} = \frac{100 R}{20} = 5 R$

Q. A diatomic ideal gas initially at 273K is given 100cal heat due to which system did 209J work. Molar heat capacity (Cm​) of gas for the process is :

23​R

25​R

45​R

5R