Question

A deutron strikes ${}_8{O}^{16}$ nucleus with the subsequent emission of an alpha particle. What will be the atomic number, mass number and chemical name of the element so produced?

• A. ${}_7{N}^{14}$
• B. ${}_7{N}^{15}$
• C. ${}_{13}A{l}^{27}$
• D. None

Answer 1

Answer: (A)

${}_8{O}^{16}+H^2{\to }_z{X}^A{+}_{2}H{e}^4$
Conservation of mass number:
$A+4=16+2=18,A=18-4=14$
Conservation of charge number
$Z+2=8+1=9$
$Z=9-2=7$
$\therefore$ Element $={}_7{N}^{14}$