Question

A deutron strikes $_{8} O ^{16}$ nucleus with the subsequent emission of an alpha particle. What will be the atomic number, mass number and chemical name of the element so produced?

• A. $_{7} N ^{14}$
• B. $_{7} N ^{15}$
• C. ${ }_{13} Al ^{27}$
• D. None

Answer 1

Answer: (A)

$_{8} O ^{16}+ H ^{2} \rightarrow_{ z } X ^{ A }+_{2} He ^{4}$
Conservation of mass number:
$A+4=16+2=18, \quad A=18-4=14$
Conservation of charge number
$Z+2=8+1=9$
$Z=9-2=7$
$\therefore $ Element $={ }_{7} N ^{14}$