A cylindrical container containing water has a small hole at height of H = 8 cm from the bottom and at a depth of 2 cm from the top surface of the liquid. The maximum horizontal distance travelled by the water before it hits the ground (x) is

Question

A cylindrical container containing water has a small hole at height of H = 8 cm from the bottom and at a depth of 2 cm from the top surface of the liquid. The maximum horizontal distance travelled by the water before it hits the ground (x) is (A) 4 cm (B) 8 cm (C) 6 cm (D) 4√2 cm

Tardigrade Admin · Accepted Answer

v=√2 gh=√2×10×2=√40 t=√(2 h/g) R=v.t=√404√(2×8/10)=8 cm.

Q. A cylindrical container containing water has a small hole at height of H = 8 cm from the bottom and at a depth of 2 cm from the top surface of the liquid. The maximum horizontal distance travelled by the water before it hits the ground (x) is

4 cm

8 cm

6 cm

$42 c m$

$v = 2 g h = 2 \times 10 \times 2 = 40$
$t = \frac{2 h}{g}$
$R = v . t = 4 0^{4} \frac{2 \times 8}{10} = 8 c m .$