Question

A cylindrical capillary tube of $0.2mm$ radius is made by joining two capillaries $T_1$ and $T_2$ of different materials having water contact angles of $0^{\circ }$ and $60^{\circ }$, respectively. The capillary tube is dipped vertically in water in two different configurations, case I and II as shown in figure. Which of the following option(s) is(are) correct?
[Surface tension of water = 0.075 N/m, density of water = $1000kg/m^3$, take $g=10m/s^2$]

• A. The correction in the height of water column raised in the tube, due to weight of water contained in the meniscus, will be different for both cases
• B. For case II, if the capillary joint is 5 cm above the water surface, the height of water column raised in the tube will be 3.75 cm. (Neglect the weight of the water in the meniscus)
• C. For case I, if the joint is kept at 8 cm above the water surface, the height of water column in the tube will be 7.5 cm. (Neglect the weight of the water in the meniscus)
• D. For case I, if the capillary joint is 5 cm above the water surface, the height of water column raised in the tube will be more than 8.75 cm. (Neglect the weight of the water in the meniscus)

Answer 1

Answer: (A), (B), (C)

For A : $h=\frac{2Tcos60^{\circ }}{\rho gr}=\frac{2\times 0.075\times 1}{10^3\times 10\times 2\times 10^{-4}\times 2}\times 100cm=3.75cm$
$\Rightarrow$ Option A is correct
For B : $h=\frac{2Tcos0}{\rho gr}=7.5cm$
$\Rightarrow$ Option B is correct
For C : Angle of contact will adjust to make h = 5 cm
For D : The shape of meniscus is different in the two cases
$\Rightarrow$ Correction is different