A cylinder with fixed capacity of 67.2 lit contains helium gas at STP. The amount of heat (in joule) needed to raise the temperature of the gas by 20°C is: [Given that R = 8.31 J mol-1 K -1]

Question

A cylinder with fixed capacity of 67.2 lit contains helium gas at STP. The amount of heat (in joule) needed to raise the temperature of the gas by 20°C is: [Given that R = 8.31 J mol-1 K -1] (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

As the process is isochoric so, Q = ncv Δ T = (67.2/22.4) × (3R/2) × 20 = 90R = 90 × 8.31 ≃ 748 j

Q. A cylinder with fixed capacity of $67.2$ lit contains helium gas at STP. The amount of heat (in joule) needed to raise the temperature of the gas by $2 0^{\circ} C$ is :
[Given that $R = 8.31 J m o l^{- 1} K^{- 1}]$

As the process is isochoric so,
$Q = n c_{v} Δ T = \frac{67.2}{22.4} \times \frac{3 R}{2} \times 20$
$= 90 R = 90 \times 8.31 ≃ 748 j$

Q. A cylinder with fixed capacity of 67.2 lit contains helium gas at STP. The amount of heat (in joule) needed to raise the temperature of the gas by 20∘C is : [Given that R=8.31Jmol−1K−1]

As the process is isochoric so, Q=ncv​ΔT=22.467.2​×23R​×20 =90R=90×8.31≃748j

Q. A cylinder with fixed capacity of $67.2$ lit contains helium gas at STP. The amount of heat (in joule) needed to raise the temperature of the gas by $2 0^{\circ} C$ is :
[Given that $R = 8.31 J m o l^{- 1} K^{- 1}]$

As the process is isochoric so,
$Q = n c_{v} Δ T = \frac{67.2}{22.4} \times \frac{3 R}{2} \times 20$
$= 90 R = 90 \times 8.31 ≃ 748 j$