A cylinder of fixed capacity 44.8 L contains a monoatomic gas at standard temperature and pressure. The amount of heat required to raise the temperature of cylinder by 10° C will be (R = universal gas constant)

Question

A cylinder of fixed capacity 44.8 L contains a monoatomic gas at standard temperature and pressure. The amount of heat required to raise the temperature of cylinder by 10° C will be (R = universal gas constant) (A) R (B) 10 R (C) 20 R (D) 30 R

Tardigrade Admin · Accepted Answer

As we know 1 mole of any ideal gas at STP occupies a volume of 22.4 L Hence, number of moles of gas μ =(44.8/22.4)=2 Since, the volume of cylinder is fixed. Hence, (Δ Q)V=μ CVΔ T =2× (3/2)R× 10=30R( ∵ (CV)mono=(3/2)R )

Q. A cylinder of fixed capacity 44.8 L contains a monoatomic gas at standard temperature and pressure. The amount of heat required to raise the temperature of cylinder by $10^{\circ} C$ will be (R = universal gas constant)

R

10 R

20 R

30 R

As we know 1 mole of any ideal gas at STP occupies a volume of $22.4 L$ Hence, number of moles of gas $μ = \frac{44.8}{22.4} = 2$ Since, the volume of cylinder is fixed. Hence, $(Δ Q)_{V} = μ C_{V} Δ T$ $= 2 \times \frac{3}{2} R \times 10 = 30 R (∵ (C_{V})_{m o n o} = \frac{3}{2} R)$

Q. A cylinder of fixed capacity 44.8 L contains a monoatomic gas at standard temperature and pressure. The amount of heat required to raise the temperature of cylinder by 10∘C will be (R = universal gas constant)

R

10 R

20 R

30 R

As we know 1 mole of any ideal gas at STP occupies a volume of 22.4L Hence, number of moles of gas μ=22.444.8​=2 Since, the volume of cylinder is fixed. Hence, (ΔQ)V​=μCV​ΔT =2×23​R×10=30R(∵(CV​)mono​=23​R)

Q. A cylinder of fixed capacity 44.8 L contains a monoatomic gas at standard temperature and pressure. The amount of heat required to raise the temperature of cylinder by $10^{\circ} C$ will be (R = universal gas constant)

As we know 1 mole of any ideal gas at STP occupies a volume of $22.4 L$ Hence, number of moles of gas $μ = \frac{44.8}{22.4} = 2$ Since, the volume of cylinder is fixed. Hence, $(Δ Q)_{V} = μ C_{V} Δ T$ $= 2 \times \frac{3}{2} R \times 10 = 30 R (∵ (C_{V})_{m o n o} = \frac{3}{2} R)$