A cylinder contains hydrogen gas at pressure of 249 kPa and temperature 27° C. Its density is :(R = 8.3 J mol-1K-1)

Question

A cylinder contains hydrogen gas at pressure of 249 kPa and temperature 27° C. Its density is :(R = 8.3 J mol-1K-1) (A) 0.5 kg/m3 (B) 0.2 kg/m3 (C) 0.1 kg/m3 (D) 0.02 kg/m3

Tardigrade Admin · Accepted Answer

We can express, an ideal gas equation as (P/ρ)=(R.T/Mw) ⇒ ρ=(pMw/RT) =(249 × 103× 2 × 10-3/8.314 × 300) =0.199 ⇒ ρ=0.2 kg/m3

Q. A cylinder contains hydrogen gas at pressure of 249 kPa and temperature $2 7^{\circ} C$ . Its density is : $(R = 8.3 J m o l^{- 1} K^{- 1}$ )

$0.5 k g / m^{3}$

$0.2 k g / m^{3}$

$0.1 k g / m^{3}$

$0.02 k g / m^{3}$

We can express, an ideal gas equation as
$\frac{P}{ρ} = \frac{R . T}{Mw}$
$\Rightarrow ρ = \frac{pMw}{RT}$
$= \frac{249 \times 1 0 ^{3} \times 2 \times 1 0 ^{- 3}}{8.314 \times 300}$
$= 0.199$
$\Rightarrow ρ = 0.2 k g / m^{3}$

Q. A cylinder contains hydrogen gas at pressure of 249 kPa and temperature 27∘C. Its density is :(R=8.3Jmol−1K−1)

0.5kg/m3

0.2kg/m3

0.1kg/m3

0.02kg/m3