A cylinder contains 10 kg of gas at a pressure of 107 N m-2. The quantity of gas taken out of the cylinder, if final pressure is 2.5 × 106 N m-2 is

Question

A cylinder contains 10 kg of gas at a pressure of 107 N m-2. The quantity of gas taken out of the cylinder, if final pressure is 2.5 × 106 N m-2 is (A) 9.5 kg (B) 7.5 kg (C) 14.2 kg (D) zero

Tardigrade Admin · Accepted Answer

(P1/P2) = (ρ1/ρ2) = (m1/m2) m2 = (P1/P2) × m1 = (2.5 × 106/107)×10 = 2.5 kg Mass of gas taken out = 10 - 2.5 = 7.5 kg

Q. A cylinder contains $10 k g$ of gas at a pressure of $1 0^{7} N m^{- 2}$ . The quantity of gas taken out of the cylinder, if final pressure is $2.5 \times 1 0^{6} N m^{- 2}$ is

$9.5 k g$

$7.5 k g$

$14.2 k g$

zero

$\frac{P _{1}}{P _{2}} = \frac{ρ _{1}}{ρ _{2}} = \frac{m _{1}}{m _{2}}$
$m_{2} = \frac{P _{1}}{P _{2}} \times m_{1} = \frac{2.5 \times 1 0 ^{6}}{1 0 ^{7}} \times 10 = 2.5 k g$
Mass of gas taken out $= 10 - 2.5 = 7.5 k g$

Q. A cylinder contains 10kg of gas at a pressure of 107Nm−2. The quantity of gas taken out of the cylinder, if final pressure is 2.5×106Nm−2 is

9.5kg

7.5kg

14.2kg