A cylinder containing an ideal gas (0.1 mol of 1.0 dm3) is in thermal equilibrium with a large volume of 0.5 molal aqueous solution of ethylene glycol at its freezing point. If the stoppers S1 and S2 (as shown in the figure) are suddenly withdrawn, the volume of the gas in litres after equilibrium is achieved w ill be. (Given, Kf(water) = 2.0 K kg mol-1, R = 0.08 dm3 atm K -1 mol-1) Given 552

Question

A cylinder containing an ideal gas (0.1 mol of 1.0 dm3) is in thermal equilibrium with a large volume of 0.5 molal aqueous solution of ethylene glycol at its freezing point. If the stoppers S1 and S2 (as shown in the figure) are suddenly withdrawn, the volume of the gas in litres after equilibrium is achieved w ill be. (Given, Kf(water) = 2.0 K kg mol-1, R = 0.08 dm3 atm K -1 mol-1) Given 552 (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

0-T f ' =2×0.5=1 Tf '=- 1ÂºC = 272 K for gas P=(0.1×0.08×272/1) P=2.176 atm P1V1=P2V2 2.176×1=1× V2 V2=2.176 litre

0−Tf′​=2×0.5=1 Tf′​=−1ºC=272K<br/>forgasP=10.1×0.08×272​ P=2.176atm<br/>P1​V1​=P2​V2​ 2.176×1=1×V2​ V2​=2.176litre

$0 - T_{f^{'}} = 2 \times 0.5 = 1$
$T_{f^{'}} = - 1º C = 272 K < b r / > f or g a s P = \frac{0.1 \times 0.08 \times 272}{1}$
$P = 2.176 a t m < b r / > P_{1} V_{1} = P_{2} V_{2}$
$2.176 \times 1 = 1 \times V_{2}$
$V_{2} = 2.176 l i t re$