Question

A cyclotron is used to accelerate protons $\left(\genfrac{}{}{0ex}{}{1H}{1}\right)$, Deuterons $\left(\genfrac{}{}{0ex}{}{2H}{1}\right)$ and $\alpha$-particles $\left(\genfrac{}{}{0ex}{}{4He}{2}\right)$. While exiting under similar conditions, the minimum K.E. is gained by

• A. $\alpha$-particle
• B. Proton
• C. Deuteron
• D. Same for all

Answer 1

Answer: (C)

K.E. $=q^2/m$
Hence, a deuteron gains the least kinetic energy.