A cyclotron is accelerating proton, where the applied magnetic field is 2 T and the potential gap is 100 textkeV . To acquire kinetic energy of 20 textMeV , the number of turns, the proton has to move between the dees is

Question

A cyclotron is accelerating proton, where the applied magnetic field is 2 T and the potential gap is 100 textkeV . To acquire kinetic energy of 20 textMeV , the number of turns, the proton has to move between the dees is (A) 200 (B) 300 (C) 150 (D) 100

Tardigrade Admin · Accepted Answer

Energy gained in one movement across the gap is 100 textkeV Therefore the energy gained in one turn is 200 textkeV N=(20 M e V/200 textkeV)=(20 × 1 06/200 × 1 03)=100

Q. A cyclotron is accelerating proton, where the applied magnetic field is $2 T$ and the potential gap is $100 keV$ . To acquire kinetic energy of $20 MeV$ , the number of turns, the proton has to move between the dees is

$200$

$300$

$150$

$100$

Energy gained in one movement across the gap is $100 keV$
Therefore the energy gained in one turn is $200 keV$
$N = \frac{20 M e V}{200 keV} = \frac{20 \times 1 0 ^{6}}{200 \times 1 0 ^{3}} = 100$

Q. A cyclotron is accelerating proton, where the applied magnetic field is 2T and the potential gap is 100keV . To acquire kinetic energy of 20MeV , the number of turns, the proton has to move between the dees is

200

300

150

100