A cyclist starts from centre O of a circular park of radius 1 km and moves along the path OPRQO as shown in figure. If he maintains constant speed of 10 ms-1, what is his acceleration at point R ?

Question

A cyclist starts from centre O of a circular park of radius 1 km and moves along the path OPRQO as shown in figure. If he maintains constant speed of 10 ms-1, what is his acceleration at point R ? (A) 10 ms-2 (B) 0.1 ms-2 (C) 0.01 ms-2 (D) 1 ms-2

Tardigrade Admin · Accepted Answer

The acceleration at point R is towards the centre of the circle. Here, v = 10 ms -1, r = 1 km = 1000 m Centripetal acceleration, ac=(v2/r) =((10 ms-1)2/1000 m) =0.1 ms-2

Q. A cyclist starts from centre $O$ of a circular park of radius $1 km$ and moves along the path $OPRQO$ as shown in figure. If he maintains constant speed of $10 m s^{- 1}$ , what is his acceleration at point $R$ ?

$10 m s^{- 2}$

$0.1 m s^{- 2}$

$0.01 m s^{- 2}$

$1 m s^{- 2}$

The acceleration at point $R$ is towards the centre of the circle.
Here, $v = 10 m s^{- 1}$ ,
$r = 1 km = 1000 m$
Centripetal acceleration, $a_{c} = \frac{v ^{2}}{r}$
$= \frac{( 10 m s ^{- 1} ) ^{2}}{1000 m}$
$= 0.1 m s^{- 2}$

Q. A cyclist starts from centre O of a circular park of radius 1km and moves along the path OPRQO as shown in figure. If he maintains constant speed of 10ms−1, what is his acceleration at point R ?

10ms−2

0.1ms−2

0.01ms−2

1ms−2