Question

A cyclist moving at a speed of $20m/s$ takes a turn, if he doubles his speed then chance of overturn:

• A. is doubled
• B. is halved
• C. becomes four times
• D. becomes 1/4 times

Answer 1

Answer: (D)

When a cyclist moves on a circular path, it experience a centrifugal force which is equal to $m{v}^2/r$ .It tries to overturn the cyclist in outward direction.If speed increase twice, the value of centrifugal force too increase to 4 times its earlier value.Therefore the change of overturning in $1/4$ times.