A cyclic process is shown in the figure. Work done during the cyclic process ABCDA is

Question

A cyclic process is shown in the figure. Work done during the cyclic process ABCDA is (A) 1600 J (B) 150 J (C) 600 J (D) 900 J

Tardigrade Admin · Accepted Answer

Work done during cyclic process ABCDA = area enclosed by ABCDA <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/cba272084a068972c4d98f188bc05008-.png" /> = ( (AB + CD/2) ) × AD = ((2 + 1)/2) × 102 = 1.5 × 102 J = 150 J

Q. A cyclic process is shown in the figure. Work done during the cyclic process ABCDA is

1600 J

150 J

600 J

900 J

Work done during cyclic process $A BC D A$
= area enclosed by $A BC D A$

$= (\frac{A B + C D}{2}) \times A D = \frac{( 2 + 1 )}{2} \times 1 0^{2}$
$= 1.5 \times 1 0^{2} J = 150 J$

Q. A cyclic process is shown in the figure. Work done during the cyclic process ABCDA is

1600 J

150 J

600 J

900 J

Work done during cyclic process ABCDA = area enclosed by ABCDA =(2AB+CD​)×AD=2(2+1)​×102 =1.5×102J=150J

Work done during cyclic process $A BC D A$
= area enclosed by $A BC D A$

$= (\frac{A B + C D}{2}) \times A D = \frac{( 2 + 1 )}{2} \times 1 0^{2}$
$= 1.5 \times 1 0^{2} J = 150 J$