Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. A cyclic process is shown in the figure. Work done during the cyclic process ABCDA isPhysics Question Image

JIPMERJIPMER 2012Thermodynamics

Solution:

Work done during cyclic process $ABCDA$
= area enclosed by $ABCDA$
image
$ = \left( \frac{AB + CD}{2} \right) \times AD = \frac{(2 + 1)}{2} \times 10^2$
$ = 1.5 \times 10^2 \, J = 150 \, J$