A cycle wheel of radius 0.5 m is rotated with constant angular velocity of 10 rad/s in a region of magnetic field of 0.1 T which is perpendicular to the plane of the wheel. The EMF generated between its centre and the rim is,

Question

A cycle wheel of radius 0.5 m is rotated with constant angular velocity of 10 rad/s in a region of magnetic field of 0.1 T which is perpendicular to the plane of the wheel. The EMF generated between its centre and the rim is, (A) 0.25 V (B) 0.125 V (C) 0.5 V (D) zero

Tardigrade Admin · Accepted Answer

E = (B ω l2/2) =(0.1(10)(0.5)2/2) = 0.125 v

Q. A cycle wheel of radius $0.5 m$ is rotated with constant angular velocity of $10 r a d / s$ in a region of magnetic field of $0.1 T$ which is perpendicular to the plane of the wheel. The $EMF$ generated between its centre and the rim is,

0.25 V

0.125 V

0.5 V

zero

$E = \frac{B ω l ^{2}}{2}$
$= \frac{0.1 ( 10 ) ( 0.5 ) ^{2}}{2} = 0.125 v$

Q. A cycle wheel of radius 0.5m is rotated with constant angular velocity of 10rad/s in a region of magnetic field of 0.1T which is perpendicular to the plane of the wheel. The EMF generated between its centre and the rim is,