Q.
A current of 5A is passing through a metallic wire of cross-sectional area 4×10−6m2 If the density of the charge carriers in the wire is 5 × 1026m−3, the drift speed of the electrons will be [e = 1.602 × 10−19C]
In a metal, conduction current is due to electrons given by
I=nAev ⇒ drift velocity, V=nAeI ⇒v=5×1026×4×10−6×1.602×10−195 =4×1.602×1011 =6.40810−1=1.56×10−2m/s