A current of 2 A flows in an electric circuit as shown in figure. The potential difference (VR-VS), in volts (VR. and VS are potentials at R and S respectively) is

Question

A current of 2 A flows in an electric circuit as shown in figure. The potential difference (VR-VS), in volts (VR. and VS are potentials at R and S respectively) is <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/cbb10be3bdca8e95c408a84de9c0a52c-.png" /> (A) −4 (B) +2 (C) +4 (D) −2

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Current through each arm P R Q and P S Q=1 A VP-VR=3 V ...(i) VP-VS=7 V ...(ii) From Eqs. (i) and (ii), we get VR-VS=+4 V

Q. A current of $2 A$ flows in an electric circuit as shown in figure. The potential difference $(V_{R} - V_{S})$ , in volts $(V_{R}$ and $V_{S}$ are potentials at $R$ and $S$ respectively) is

−4

+2

+4

−2

Current through each arm
$PRQ$ and $PSQ = 1 A$
$V_{P} - V_{R} = 3 V ... (i)$
$V_{P} - V_{S} = 7 V ... (ii)$
From Eqs. (i) and (ii), we get
$V_{R} - V_{S} = + 4 V$

Q. A current of 2A flows in an electric circuit as shown in figure. The potential difference (VR​−VS​), in volts (VR​ and VS​ are potentials at R and S respectively) is

−4

+2

+4

−2

Current through each arm PRQ and PSQ=1A VP​−VR​=3V...(i) VP​−VS​=7V...(ii) From Eqs. (i) and (ii), we get VR​−VS​=+4V

Q. A current of $2 A$ flows in an electric circuit as shown in figure. The potential difference $(V_{R} - V_{S})$ , in volts $(V_{R}$ and $V_{S}$ are potentials at $R$ and $S$ respectively) is

Current through each arm
$PRQ$ and $PSQ = 1 A$
$V_{P} - V_{R} = 3 V ... (i)$
$V_{P} - V_{S} = 7 V ... (ii)$
From Eqs. (i) and (ii), we get
$V_{R} - V_{S} = + 4 V$