A current of 10 A is maintained in a conductor of cross-section 1 cm 2. If the number density of free electrons be 9 × 1028 m -3, the drift velocity of free electrons is

Question

A current of 10 A is maintained in a conductor of cross-section 1 cm 2. If the number density of free electrons be 9 × 1028 m -3, the drift velocity of free electrons is (A) 6.94 × 10-6 m / s (B) 5.94 × 10-2 m / s (C) 1.94 × 10-3 m / s (D) 2.94 × 10-4 m / s

Tardigrade Admin · Accepted Answer

i=n e A Vd 10=(9 × 1028)(1.6 × 10-19)(10-4) VD Solving, we get VD=6.94 × 10-6 m / s

Q. A current of $10 A$ is maintained in a conductor of cross-section $1 c m^{2}$ . If the number density of free electrons be $9 \times 1 0^{28} m^{- 3}$ , the drift velocity of free electrons is

$6.94 \times 1 0^{- 6} m / s$

$5.94 \times 1 0^{- 2} m / s$

$1.94 \times 1 0^{- 3} m / s$

$2.94 \times 1 0^{- 4} m / s$

$i = n e A V_{d}$
$10 = (9 \times 1 0^{28}) (1.6 \times 1 0^{- 19}) (1 0^{- 4}) V_{D}$
Solving, we get
$V_{D} = 6.94 \times 1 0^{- 6} m / s$

Q. A current of 10A is maintained in a conductor of cross-section 1cm2. If the number density of free electrons be 9×1028m−3, the drift velocity of free electrons is

6.94×10−6m/s

5.94×10−2m/s

1.94×10−3m/s

2.94×10−4m/s