A current of 10 A is flowing in a wire of length 1.5 m. A force of 15 N acts on it when it is placed in a uniform magnetic field of 2 T. The angle between the magnetic field and the direction of the current is

Question

A current of 10 A is flowing in a wire of length 1.5 m. A force of 15 N acts on it when it is placed in a uniform magnetic field of 2 T. The angle between the magnetic field and the direction of the current is (A) 30° (B) 45° (C) 60° (D) 90°

Tardigrade Admin · Accepted Answer

F=IlB sin θ or sin θ = (F/IlB) sin θ = (15/10×1.5×2)=(1/2) or θ=30°

Q. $A$ current of $10 A$ is flowing in a wire of length $1.5 m$ . A force of $15 N$ acts on it when it is placed in a uniform magnetic field of $2 T$ . The angle between the magnetic field and the direction of the current is

$3 0^{\circ}$

$4 5^{\circ}$

$6 0^{\circ}$

$9 0^{\circ}$

$F = I lB s in θ$ or $s in θ = \frac{F}{I lB}$
$s in θ = \frac{15}{10 \times 1.5 \times 2} = \frac{1}{2}$
or $θ = 3 0^{\circ}$

Q. A current of 10A is flowing in a wire of length 1.5m. A force of 15N acts on it when it is placed in a uniform magnetic field of 2T. The angle between the magnetic field and the direction of the current is

30∘

45∘

60∘

90∘