A current I is flowing through the loop, as shown in the figure. The magnetic field at centre O is

Question

A current I is flowing through the loop, as shown in the figure. The magnetic field at centre O is <img class="img-fluid question-image" alt="Question" src="https://cdn.tardigrade.in/q/nta/p-bpddetrygzc8.png" /> (A) (7 μ 0 I/16 R) bigotimes (B) (7 μ 0 I/16 R) odot (C) (5 μ 0 I/16 R) bigotimes (D) (5 μ 0 I/16 R) odot

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="Solution" src="https://cdn.tardigrade.in/q/nta/p-bpddetry70cz.png" /> B=B1+B2 =(μ0 I/2 r1)((3 π / 2/2 π))+(μ0 I/2 r2)((π / 2/2 π)) =(3/8) (μ0 I/R)+(μ0 I/2(2 R)) × (1/4) =(7/16) (μ 0 I/R) bigotimes

Q. A current $I$ is flowing through the loop, as shown in the figure. The magnetic field at centre $O$ is

$\frac{7 μ _{0} I}{16 R} ⨂$

$\frac{7 μ _{0} I}{16 R} ⊙$

$\frac{5 μ _{0} I}{16 R} ⨂$

$\frac{5 μ _{0} I}{16 R} ⊙$

$B = B_{1} + B_{2}$
$= \frac{μ _{0} I}{2 r _{1}} (\frac{3 π /2}{2 π}) + \frac{μ _{0} I}{2 r _{2}} (\frac{π /2}{2 π})$
$= \frac{3}{8} \frac{μ _{0} I}{R} + \frac{μ _{0} I}{2 ( 2 R )} \times \frac{1}{4}$
$= \frac{7}{16} \frac{μ _{0} I}{R} ⨂$

Q. A current I is flowing through the loop, as shown in the figure. The magnetic field at centre O is

16R7μ0​I​⨂

16R7μ0​I​⊙

16R5μ0​I​⨂

16R5μ0​I​⊙