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Q. A current $I$ is flowing through the loop, as shown in the figure. The magnetic field at centre $O$ is

Question

NTA AbhyasNTA Abhyas 2020Moving Charges and Magnetism

Solution:

Solution
$B=B_{1}+B_{2}$
$=\frac{\mu_0 I}{2 r_1}\left(\frac{3 \pi / 2}{2 \pi}\right)+\frac{\mu_0 I}{2 r_2}\left(\frac{\pi / 2}{2 \pi}\right)$
$=\frac{3}{8} \frac{\mu_0 I}{R}+\frac{\mu_0 I}{2(2 R)} \times \frac{1}{4}$
$=\frac{7}{16} \, \frac{\mu _{0} I}{R}\bigotimes$