A current i ampere flows in a circular arc of wire which subtends an angle (3 π/2) radian at its center, whose radius is R. The magnetic field B at its center is

Question

A current i ampere flows in a circular arc of wire which subtends an angle (3 π/2) radian at its center, whose radius is R. The magnetic field B at its center is (A) (μ0 i/R) (B) (3 μ0 i/2 R) (C) (3 μ0 i/4 R) (D) (3 μ0 i/8 R)

Tardigrade Admin · Accepted Answer

B=(μ0 i/2 R)((3 π/2(2 π)))=(3 μ0 i/8 R)

Q. A current $i$ ampere flows in a circular arc of wire which subtends an angle $\frac{3 π}{2}$ radian at its center, whose radius is $R$ . The magnetic field $B$ at its center is

$\frac{μ _{0} i}{R}$

$\frac{3 μ _{0} i}{2 R}$

$\frac{3 μ _{0} i}{4 R}$

$\frac{3 μ _{0} i}{8 R}$

$B = \frac{μ _{0} i}{2 R} (\frac{3 π}{2 ( 2 π )}) = \frac{3 μ _{0} i}{8 R}$

Q. A current i ampere flows in a circular arc of wire which subtends an angle 23π​ radian at its center, whose radius is R. The magnetic field B at its center is

Rμ0​i​

2R3μ0​i​

4R3μ0​i​

8R3μ0​i​