A current-carrying wire of area A, length l, number of density of charge carriers n is placed in a region of external magnetic field B. What will be net force on charged carriers?

Question

A current-carrying wire of area A, length l, number of density of charge carriers n is placed in a region of external magnetic field B. What will be net force on charged carriers? (A) (n A l) q( v d × B ) (B) q( v d × B ) (C) n q( v d × B ) (D) A l q( v d × B )

Tardigrade Admin · Accepted Answer

The total number of mobile charge carriers in wire will be

n A l

.
For a steady current

I

in this conducting wire, we may assume that each mobile carrier has an average drift velocity

v_{d}

.
In the presence of an external magnetic field

B

, the force on these carriers is given by

F = (n A l) q (v_{d} \times B)

Q. A current-carrying wire of area $A$ , length $l$ , number of density of charge carriers $n$ is placed in a region of external magnetic field $B$ . What will be net force on charged carriers?

$(n A l) q (v_{d} \times B)$

$q (v_{d} \times B)$

$n q (v_{d} \times B)$

$A lq (v_{d} \times B)$

Q. A current-carrying wire of area A, length l, number of density of charge carriers n is placed in a region of external magnetic field B. What will be net force on charged carriers?

(nAl)q(vd​×B)

q(vd​×B)

nq(vd​×B)

Alq(vd​×B)

The total number of mobile charge carriers in wire will be nAl. For a steady current I in this conducting wire, we may assume that each mobile carrier has an average drift velocity vd​. In the presence of an external magnetic field B, the force on these carriers is given by F=(nAl)q(vd​×B)

Q. A current-carrying wire of area $A$ , length $l$ , number of density of charge carriers $n$ is placed in a region of external magnetic field $B$ . What will be net force on charged carriers?

$(n A l) q (v_{d} \times B)$

$q (v_{d} \times B)$

$n q (v_{d} \times B)$

$A lq (v_{d} \times B)$