A current-carrying square loop is placed near an infinitely long current-carrying wire as shown in the figure. The torque acting on the loop is

Question

A current-carrying square loop is placed near an infinitely long current-carrying wire as shown in the figure. The torque acting on the loop is <img class="img-fluid question-image" alt="Question" src="https://cdn.tardigrade.in/q/nta/p-wsxpsjewidcm2zog.jpg" /> (A) (μ 0/2 π ) i1i2r (B) (μ 0/2 π ) i1i2 loge 2 (C) (μ 0/2 π )(i1 i2 r/2) (D)  textZero

Tardigrade Admin · Accepted Answer

The force acting on the loop PQRSP due to current i1 through the long wire are acting in the plane of loop. Due to which, the torque on loop is zero.

Q. A current-carrying square loop is placed near an infinitely long current-carrying wire as shown in the figure. The torque acting on the loop is

$\frac{μ _{0}}{2 π} i_{1} i_{2} r$

$\frac{μ _{0}}{2 π} i_{1} i_{2} lo g_{e} 2$

$\frac{μ _{0}}{2 π} \frac{i _{1} i _{2} r}{2}$

$Zero$

The force acting on the loop $PQRSP$ due to current $i_{1}$ through the long wire are acting in the plane of loop. Due to which, the torque on loop is zero.

Q. A current-carrying square loop is placed near an infinitely long current-carrying wire as shown in the figure. The torque acting on the loop is

2πμ0​​i1​i2​r

2πμ0​​i1​i2​loge​2

2πμ0​​2i1​i2​r​

Zero

The force acting on the loop PQRSP due to current i1​ through the long wire are acting in the plane of loop. Due to which, the torque on loop is zero.

$\frac{μ _{0}}{2 π} i_{1} i_{2} r$

$\frac{μ _{0}}{2 π} i_{1} i_{2} lo g_{e} 2$

$\frac{μ _{0}}{2 π} \frac{i _{1} i _{2} r}{2}$

$Zero$

The force acting on the loop $PQRSP$ due to current $i_{1}$ through the long wire are acting in the plane of loop. Due to which, the torque on loop is zero.