A current carrying square loop is placed near a straight infinitely long current carrying wire as shown in figure. The torque acting on the loop is

Question

A current carrying square loop is placed near a straight infinitely long current carrying wire as shown in figure. The torque acting on the loop is (A) (μ0 / 2π) (i1i2l/ab) (B) (μ0 / 2π) (i1i2l/a(a + b)) (C) (μ0 / 2π) (i1i2l (b - a)/ab) (D) 0

Tardigrade Admin · Accepted Answer

The forces acting on the sides of the square due to cureent i, all lie in the planes of the coil. Therefore, there is no net torque.

Q. A current carrying square loop is placed near a straight infinitely long current carrying wire as shown in figure. The torque acting on the loop is

$\frac{μ _{0}}{2 π} \frac{i _{1} i _{2} l}{ab}$

$\frac{μ _{0}}{2 π} \frac{i _{1} i _{2} l}{a ( a + b )}$

$\frac{μ _{0}}{2 π} \frac{i _{1} i _{2} l ( b - a )}{ab}$

0

The forces acting on the sides of the square due to cureent $i$ , all lie in the planes of the coil. Therefore, there is no net torque.

Q. A current carrying square loop is placed near a straight infinitely long current carrying wire as shown in figure. The torque acting on the loop is

2πμ0​​abi1​i2​l​

2πμ0​​a(a+b)i1​i2​l​

2πμ0​​abi1​i2​l(b−a)​

0

The forces acting on the sides of the square due to cureent i, all lie in the planes of the coil. Therefore, there is no net torque.

$\frac{μ _{0}}{2 π} \frac{i _{1} i _{2} l}{ab}$

$\frac{μ _{0}}{2 π} \frac{i _{1} i _{2} l}{a ( a + b )}$

$\frac{μ _{0}}{2 π} \frac{i _{1} i _{2} l ( b - a )}{ab}$

The forces acting on the sides of the square due to cureent $i$ , all lie in the planes of the coil. Therefore, there is no net torque.