A current carrying coil is placed with its axis perpendicular to N-S direction. Let horizontal component of earth's magnetic field be H0 and magnetic field inside the loop be H . If a magnet is suspended inside the loop, it makes angle θ with H. Then θ=

Question

A current carrying coil is placed with its axis perpendicular to N-S direction. Let horizontal component of earth's magnetic field be H0 and magnetic field inside the loop be H . If a magnet is suspended inside the loop, it makes angle θ with H. Then θ= (A)  tan -1((H0/H)) (B)  tan -1((H/H0)) (C)  operatornamecosec-1((H/H0)) (D)  cot -1((H0/H))

Tardigrade Admin · Accepted Answer

In given case H and H0 are perpendicular to each other. <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/a43afcb8fe30a84cf7f44aec20561bb2-.png" /> From figure, tan θ=(H0/H) ⇒ θ= tan -1((H0/H))

Q. A current carrying coil is placed with its axis perpendicular to $N - S$ direction. Let horizontal component of earth's magnetic field be $H_{0}$ and magnetic field inside the loop be $H .$ If a magnet is suspended inside the loop, it makes angle $θ$ with $H$ . Then $θ =$

$tan^{- 1} (\frac{H _{0}}{H})$

$tan^{- 1} (\frac{H}{H _{0}})$

$cosec^{- 1} (\frac{H}{H _{0}})$

$cot^{- 1} (\frac{H _{0}}{H})$

In given case $H$ and $H_{0}$ are perpendicular to each other.

From figure, $tan θ = \frac{H _{0}}{H}$
$\Rightarrow θ = tan^{- 1} (\frac{H _{0}}{H})$

Q. A current carrying coil is placed with its axis perpendicular to N−S direction. Let horizontal component of earth's magnetic field be H0​ and magnetic field inside the loop be H. If a magnet is suspended inside the loop, it makes angle θ with H. Then θ=

tan−1(HH0​​)

tan−1(H0​H​)

cosec−1(H0​H​)

cot−1(HH0​​)