Question

A current carrying circular loop of radius $R$ is placed in the $x-y$ plane with centre at the origin. Half of the loop with $x>0$ is now bent so that it now lies in the $y-z$ plane

• A. The magnitude of magnetic moment now diminishes
• B. The magnetic moment does not change
• C. The magnitude of $\vec{B}$ at $(0,0,z),z>>R$ increases
• D. The magnitude of $\vec{B}$ at $(0,0,z),z>>R$ is unchanged

Answer 1

Answer: (A)

For a circular loop of radius $R$ carrying current $I$ placed in $x-y$ plane, the magnetic moment $M=I\times \pi R^2$. It acts perpendicular to the loop i.e., along $z$-direction. When half of the current loop is bent in $y-z$ plane, then magnetic moment due to half current loop in $x-y$ plane, $M_1=I(\pi R^2/2)$ acting along $z$-direction. Magnetic moment due to half current loop in $y-z$ plane, $M_2=I(\pi R^2/2)$ along $x$ -direction.
Effective magnetic moment due to entire bent current loop,
$M^{\prime }=\sqrt{M_1^2+M_2^2}$
$=\sqrt{{\left(I\pi R^2/2\right)}^2+{\left(I\pi R^2/2\right)}^2}$
$=\frac{I\pi R^2}{2}\sqrt{2}<M$
i.e., magnetic moment diminishes.