A current carring loop consists of 3 identical quarter circular of radius R, lying in the positive quadrants of the x-y, y-z and z-x planes with their centres at the origin, joined together then magnitude of magnetic field at origin is

Question

A current carring loop consists of 3 identical quarter circular of radius R, lying in the positive quadrants of the x-y, y-z and z-x planes with their centres at the origin, joined together then magnitude of magnetic field at origin is (A) (μoI/8R) (B) (√3μoI/8R) (C) (μoi/4R) (D) (μoI/√3R)

Tardigrade Admin · Accepted Answer

Bo=√3Barc = √3((μoi/4(2R))) Bo = (√3μoi/R)

Q. A current carring loop consists of 3 identical quarter circular of radius R, lying in the positive quadrants of the x-y, y-z and z-x planes with their centres at the origin, joined together then magnitude of magnetic field at origin is

$\frac{μ _{o I}}{8 R}$

$\frac{3 μ _{o I}}{8 R}$

$\frac{μ _{o} i}{4 R}$

$\frac{μ _{o} I}{3 R}$

$B_{o} = 3 B_{a rc}$
$= 3 (\frac{μ _{o} i}{4 ( 2 R )})$
$B_{o} = \frac{3 μ _{o} i}{R}$

Q. A current carring loop consists of 3 identical quarter circular of radius R, lying in the positive quadrants of the x-y, y-z and z-x planes with their centres at the origin, joined together then magnitude of magnetic field at origin is

8RμoI​​

8R3​μoI​​

4Rμo​i​

3​Rμo​I​

Bo​=3​Barc​ =3​(4(2R)μo​i​) Bo​=R3​μo​i​

$\frac{μ _{o I}}{8 R}$

$\frac{3 μ _{o I}}{8 R}$

$\frac{μ _{o} i}{4 R}$

$\frac{μ _{o} I}{3 R}$

$B_{o} = 3 B_{a rc}$
$= 3 (\frac{μ _{o} i}{4 ( 2 R )})$
$B_{o} = \frac{3 μ _{o} i}{R}$