A cubical vessel of height 1 m is full of water. What is the amount of work done in pumping water out of the vessel? (Take g = 10 ms-2)

Question

A cubical vessel of height 1 m is full of water. What is the amount of work done in pumping water out of the vessel? (Take g = 10 ms-2) (A) 1250 J (B) 5000 J (C) 1000 J (D) 2500 J

Tardigrade Admin · Accepted Answer

The volume of water contained in the vessel would be equal to

V = l^{3} = (1 m)^{3} = l m^{3}

Assuming water to be pure so the density of water would be equal to

d = 1000 k g / m^{3},

hence the mass of water contained in the vessel would be equal to m = Vd = 1000 kg. Thus, the work done would be equal to

W = m g h = 1000 \times \frac{1}{2} = 5000 J

Q. A cubical vessel of height 1 m is full of water. What is the amount of work done in pumping water out of the vessel? (Takeg=10ms−2)

1250 J

5000 J

1000 J

2500 J

Q. A cubical vessel of height 1 m is full of water. What is the amount of work done in pumping water out of the vessel? $(T ak e g = 10 m s^{- 2})$