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Q.
A cubical vessel of height 1 m is full of water. What is the amount of work done in pumping water out of the vessel? $(Take g = 10 ms^{-2})$
Mechanical Properties of Fluids
Solution:
The volume of water contained in the vessel would be equal to $V = l^3 = (1 m)^3 =lm^3$ Assuming water to be pure so the density of water would be equal to $d = 1000kg/m^3,$ hence the mass of water contained in the vessel would be equal to m = Vd = 1000 kg. Thus, the work done would be equal to
$W =mgh =1000\times\frac{1}{2}=5000 J$