A cubical block of side a is moving with velocity v on a horizontal smooth plane as shown in figure. It hits a ridge at point O. The angular speed of the block after it hits O is

Question

A cubical block of side a is moving with velocity v on a horizontal smooth plane as shown in figure. It hits a ridge at point O. The angular speed of the block after it hits O is (A) 3 v /(4 a) (B) 3 v /(2 a) (C) √3 v / √2 a (D) zero

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/8664d9f1e01443f210a7b6cec396c0bd-.png" /> Apply conservation of angular momentum about O M v (a/2)=[(M a2/6)+M((a/√2))2] ω ⇒ ω=(3 v/4 a)

Q. A cubical block of side $a$ is moving with velocity $v$ on a horizontal smooth plane as shown in figure. It hits a ridge at point $O$ . The angular speed of the block after it hits $O$ is

$3 v / (4 a)$

$3 v / (2 a)$

$3 v / 2 a$

zero

Apply conservation of angular momentum about $O$
$M v \frac{a}{2} = [\frac{M a ^{2}}{6} + M (\frac{a}{2})^{2}] ω$
$\Rightarrow ω = \frac{3 v}{4 a}$

Q. A cubical block of side a is moving with velocity v on a horizontal smooth plane as shown in figure. It hits a ridge at point O. The angular speed of the block after it hits O is

3v/(4a)

3v/(2a)

3v​/2a​