A cubical block of side 30 cm is moving with velocity 2 ms-1 on a smooth horizontal surface. The surface has a bump at a point O as shown in figure. The angular velocity (in rad/s) of the block immediately after it hits the bump, is :

Question

A cubical block of side 30 cm is moving with velocity 2 ms-1 on a smooth horizontal surface. The surface has a bump at a point O as shown in figure. The angular velocity (in rad/s) of the block immediately after it hits the bump, is : (A) 5.0 (B) 6.7 (C) 9.4 (D) 13.3

Tardigrade Admin · Accepted Answer

mv=Iω ω=(m⋅2 (R/2)/m[(R2)6+((R)√2)2] ω=(12/8R)=(3/2×0.3)=(10/2)=5

Q. A cubical block of side $30 c m$ is moving with velocity $2 m s^{- 1}$ on a smooth horizontal surface. The surface has a bump at a point $O$ as shown in figure. The angular velocity (in rad/s) of the block immediately after it hits the bump, is :

5.0

6.7

9.4

13.3

$m v = I ω$
$ω = \frac{m \cdot 2 \frac{R}{2}}{m [ \frac{R ^{2}}{6} + ( \frac{R}{2} ) ^{2} ]}$
$ω = \frac{12}{8 R} = \frac{3}{2 \times 0.3} = \frac{10}{2} = 5$

Q. A cubical block of side 30cm is moving with velocity 2ms−1 on a smooth horizontal surface. The surface has a bump at a point O as shown in figure. The angular velocity (in rad/s) of the block immediately after it hits the bump, is :

5.0

6.7

9.4

13.3

mv=Iω ω=m[6R2​+(2​R​)2]m⋅22R​​ ω=8R12​=2×0.33​=210​=5

Q. A cubical block of side $30 c m$ is moving with velocity $2 m s^{- 1}$ on a smooth horizontal surface. The surface has a bump at a point $O$ as shown in figure. The angular velocity (in rad/s) of the block immediately after it hits the bump, is :

$m v = I ω$
$ω = \frac{m \cdot 2 \frac{R}{2}}{m [ \frac{R ^{2}}{6} + ( \frac{R}{2} ) ^{2} ]}$
$ω = \frac{12}{8 R} = \frac{3}{2 \times 0.3} = \frac{10}{2} = 5$