A cubic solid is made up of two elements X and Y. Atoms of X are present on every alternate cormer and one at the eenter of cube. Y is at (1/3) td of the total faces. The empirical formula of the compound is

Question

A cubic solid is made up of two elements X and Y. Atoms of X are present on every alternate cormer and one at the eenter of cube. Y is at (1/3) td of the total faces. The empirical formula of the compound is (A) X 2 Y 1.5 (B) X 2.5 Y (C) XY 2, 5 (D) X 1.5 Y 2

Tardigrade Admin · Accepted Answer

X4 x81+1 × 11 Y6 × (1/3) × (1/2) ⇒ X (1/2)+1 Y 1 ⇒ X (2/3) Y 1 ⇒ X 1.5 Y 1 ⇒ X 3 Y 2

Q. A cubic solid is made up of two elements $X$ and $Y$ . Atoms of $X$ are present on every alternate cormer and one at the eenter of cube. $Y$ is at $\frac{1}{3} t d$ of the total faces. The empirical formula of the compound is

$X_{2} Y_{1.5}$

$X_{2.5} Y$

$X Y_{2}, 5$

$X_{1.5} Y_{2}$

$X_{4 x_{8}^{1} + 1 \times 1}^{1} Y_{6 \times \frac{1}{3} \times \frac{1}{2}}$
$\Rightarrow X_{\frac{1}{2} + 1} Y_{1}$
$\Rightarrow X_{\frac{2}{3}} Y_{1}$
$\Rightarrow X_{1.5} Y_{1}$
$\Rightarrow X_{3} Y_{2}$

Q. A cubic solid is made up of two elements X and Y. Atoms of X are present on every alternate cormer and one at the eenter of cube. Y is at 31​td of the total faces. The empirical formula of the compound is

X2​Y1.5​

X2.5​Y

XY2​,5

X1.5​Y2​