Length of the cube, L=1.2×10−2m ∴ Volume of the cube, V=L3=(1.2×10−2)×(1.2×10−2)×(1.2×10−2)m3 ⇒V=1.728×10−6m3
But as the length contains only 2 significant digits,
thus volume must also contain 2 significant digits.
Hence, volume of the cube is 1.7×10−6m3