A crystal has bcc structure and its lattice constant is 3.6 overset texto mathop textA . What is the atomic radius?

Question

A crystal has bcc structure and its lattice constant is 3.6 overset texto mathop textA . What is the atomic radius? (A) 3.6 overset texto mathop textA  (B) 1.8 overset texto mathop textA  (C) 1.27 overset texto mathop textA  (D) 1.56 overset texto mathop textA

Tardigrade Admin · Accepted Answer

Atomic radius for bcc structure r=(a√3/4)=(3.6√3/4)=1.56 overset texto mathop textA

Q. A crystal has bcc structure and its lattice constant is 3.6 $A o$ . What is the atomic radius?

3.6 $A o$

1.8 $A o$

1.27 $A o$

1.56 $A o$

Atomic radius for bcc structure $r = \frac{a 3}{4} = \frac{3.6 3}{4} = 1.56 A o$

Q. A crystal has bcc structure and its lattice constant is 3.6 Ao . What is the atomic radius?

3.6 Ao

1.8 Ao

1.27 Ao

1.56 Ao