Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. A crystal has bcc structure and its lattice constant is 3.6 $ \overset{\text{o}}{\mathop{\text{A}}}\, $ . What is the atomic radius?

CMC MedicalCMC Medical 2011

Solution:

Atomic radius for bcc structure $ r=\frac{a\sqrt{3}}{4}=\frac{3.6\sqrt{3}}{4}=1.56\,\overset{\text{o}}{\mathop{\text{A}}}\, $