Question

A cricketer can throw a ball to a maximum horizontal distance of $100m$. With the same speed how much high above the ground can the cricketer throw the same ball?

• A. $50m$
• B. $100m$
• C. $150m$
• D. $200m$

Answer 1

Answer: (A)

Let $u$ be the velocity of projection of the ball. The ball will cover maximum horizontal distance when angle of projection with horizontal, $\theta =45^{°}$. Then $R_{max}=\frac{u^2}{g}$
Here, $R_{max}=100m$
$\therefore \frac{u^2}{g}=100m...\left(i\right)$
As $v^2-u^2=2as$
Here, $v=0$ (At highest point velocity is zero)
$a=-g$,
$s=H$
$\therefore H=\frac{u^2}{2g}=\frac{100}{2}$
$=50m$ (Using (i))