A cricket ball of mass 250 g collides with a bat with velocity 10 m/s and returns with the same velocity within 0.01 s. The force acted on bat is

Question

A cricket ball of mass 250 g collides with a bat with velocity 10 m/s and returns with the same velocity within 0.01 s. The force acted on bat is (A) 25 N (B) 50 N (C) 250 N (D) 500 N

Tardigrade Admin · Accepted Answer

The force acted on bat F=m⋅ a or F=m⋅ ( (dv/dt) ) =(0.25× [(10)-(-10)]/0.01) =25× 20=500 N

Q. A cricket ball of mass 250 g collides with a bat with velocity 10 m/s and returns with the same velocity within 0.01 s. The force acted on bat is

25 N

50 N

250 N

500 N

The force acted on bat $F = m \cdot a$ or $F = m \cdot (\frac{d v}{d t})$ $= \frac{0.25 \times [( 10 ) - ( - 10 )]}{0.01}$ $= 25 \times 20 = 500 N$

Q. A cricket ball of mass 250 g collides with a bat with velocity 10 m/s and returns with the same velocity within 0.01 s. The force acted on bat is

25 N

50 N

250 N

500 N

The force acted on bat F=m⋅a or F=m⋅(dtdv​) =0.010.25×[(10)−(−10)]​ =25×20=500N

The force acted on bat $F = m \cdot a$ or $F = m \cdot (\frac{d v}{d t})$ $= \frac{0.25 \times [( 10 ) - ( - 10 )]}{0.01}$ $= 25 \times 20 = 500 N$