A cricket ball of mass 150 g collides straight with a bat with a velocity of 10 ms -1. Batsman hits it straight back with a velocity of 20 ms -1. If ball remains in contact with bat for 0.1 s, then average force exerted by the bat on the ball is

Question

A cricket ball of mass 150 g collides straight with a bat with a velocity of 10 ms -1. Batsman hits it straight back with a velocity of 20 ms -1. If ball remains in contact with bat for 0.1 s, then average force exerted by the bat on the ball is (A) 15 N (B) 45 N (C) 150 N (D) 4.5 N

Tardigrade Admin · Accepted Answer

F=(m(v-u)/t)=(0.15[20-(-10)]/0.1)=(0.15 × 30/0.1)=45 N

Q. A cricket ball of mass $150 g$ collides straight with a bat with a velocity of $10 m s^{- 1}$ . Batsman hits it straight back with a velocity of $20 m s^{- 1}$ . If ball remains in contact with bat for $0.1 s$ , then average force exerted by the bat on the ball is

15 N

45 N

150 N

4.5 N

$F = \frac{m ( v - u )}{t} = \frac{0.15 [ 20 - ( - 10 )]}{0.1} = \frac{0.15 \times 30}{0.1} = 45 N$

Q. A cricket ball of mass 150g collides straight with a bat with a velocity of 10ms−1. Batsman hits it straight back with a velocity of 20ms−1. If ball remains in contact with bat for 0.1s, then average force exerted by the bat on the ball is