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  4. A cricket ball of mass 150 g collides straight with a bat with a velocity of 10 ms -1. Batsman hits it straight back with a velocity of 20 ms -1. If ball remains in contact with bat for 0.1 s, then average force exerted by the bat on the ball is

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Q. A cricket ball of mass $150\, g$ collides straight with a bat with a velocity of $10\, ms ^{-1}$. Batsman hits it straight back with a velocity of $20 \, ms ^{-1}$. If ball remains in contact with bat for $0.1\, s$, then average force exerted by the bat on the ball is

Laws of Motion

Solution:

$F=\frac{m(v-u)}{t}=\frac{0.15[20-(-10)]}{0.1}=\frac{0.15 \times 30}{0.1}=45 N$