A cricket ball of mass 0.15 kg is thrown vertically up by a bowling machine so that it rises to a maximum height of 20 m after leaving the machine. If the part pushing the ball applies a constant force F on the ball and moves horizontally a distance of 0.2 m while launching the ball, the value of F ( in N) is (g=10 ms -2).

Question

A cricket ball of mass 0.15 kg is thrown vertically up by a bowling machine so that it rises to a maximum height of 20 m after leaving the machine. If the part pushing the ball applies a constant force F on the ball and moves horizontally a distance of 0.2 m while launching the ball, the value of F ( in N) is (g=10 ms -2). (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

W F =(1/2) mv 2= mgh F ( S )= mgh F (0.2)=(0.15)(10)(20) F =150 N

WF​=21​mv2=mgh F(S)=mgh F(0.2)=(0.15)(10)(20) F=150N

$W_{F} = \frac{1}{2} m v^{2} = m g h$
$F (S) = m g h$
$F (0.2) = (0.15) (10) (20)$
$F = 150 N$