A cricket ball is hit with a velocity 25 ms -1, 60° above the horizontal. How far above the ground, ball passes over a fielder 50 m from the bat (consider the ball is struck very close to the ground)? Take √3=1.7 and g =10 ms -2

Question

A cricket ball is hit with a velocity 25 ms -1, 60° above the horizontal. How far above the ground, ball passes over a fielder 50 m from the bat (consider the ball is struck very close to the ground)? Take √3=1.7 and g =10 ms -2 (A) 6.8 m (B) 7 m (C) 5 m (D) 10 m

Tardigrade Admin · Accepted Answer

y=x tan θ-(1/2) (g x2/u2 cos 2 θ) y =50 tan 60°-(10 × 50 × 50/2 × 25 × 25 × cos 2 60°)=5 m

Q. A cricket ball is hit with a velocity $25 m s^{- 1}, 6 0^{\circ}$ above the horizontal. How far above the ground, ball passes over a fielder $50 m$ from the bat (consider the ball is struck very close to the ground)?
Take $3 = 1.7$ and $g = 10 m s^{- 2}$

$6.8 m$

$7 m$

$5 m$

$10 m$

$y = x tan θ - \frac{1}{2} \frac{g x ^{2}}{u ^{2} c o s ^{2} θ}$
$y = 50 tan 6 0^{\circ} - \frac{10 \times 50 \times 50}{2 \times 25 \times 25 \times c o s ^{2} 6 0 ^{\circ}} = 5 m$

Q. A cricket ball is hit with a velocity 25ms−1,60∘ above the horizontal. How far above the ground, ball passes over a fielder 50m from the bat (consider the ball is struck very close to the ground)? Take 3​=1.7 and g=10ms−2

6.8m

7m

5m

10m