A copper solid cube of 60 mm side is subjected to a pressure of 2.5× 107Pa. If the bulk modulus of copper is 1.25× 107N/m2, the change in the volume of cube is:

Question

A copper solid cube of 60 mm side is subjected to a pressure of 2.5× 107Pa. If the bulk modulus of copper is 1.25× 107N/m2, the change in the volume of cube is: (A)  - text 43.2 text m3  (B)  - text 43.2 text mm3  (C)  - text 43.2 text cm3  (D)  - text 432 text mm3

Tardigrade Admin · Accepted Answer

Bulk modulus K=(PV/Δ V) ( beginalign textGiven: textSide textof cube = 60 textcm textP = 2 text.5× text1 text07Pa K=1.25× 1011 endalign ) Δ V=(PV/K) ⇒ Δ V=(2.5× 107× 60× 60× 60/1.25× 1011) =-43.2 mm3

Q. A copper solid cube of 60 mm side is subjected to a pressure of $2.5 \times 10^{7} P a .$ If the bulk modulus of copper is $1.25 \times 10^{7} N / m^{2},$ the change in the volume of cube is:

$- 43.2 m^{3}$

$- 43.2 m m^{3}$

$- 43.2 c m^{3}$

$- 432 m m^{3}$

Bulk modulus $K = \frac{P V}{Δ V}$ $⎝ ⎛ Given: Side of cube = 60 cm P = 2 .5 \times 1 0^{7} P a K = 1.25 \times 10^{11} ⎠ ⎞$ $Δ V = \frac{P V}{K}$ $\Rightarrow$ $Δ V = \frac{2.5 \times 10 ^{7} \times 60 \times 60 \times 60}{1.25 \times 10 ^{11}}$ $= - 43.2 m m^{3}$

Q. A copper solid cube of 60 mm side is subjected to a pressure of 2.5×107Pa. If the bulk modulus of copper is 1.25×107N/m2, the change in the volume of cube is:

−43.2m3

−43.2mm3

−43.2cm3

−432mm3