A copper rod is moved in a magnetic field. The charge developed across its ends will be proportional to :

Question

A copper rod is moved in a magnetic field. The charge developed across its ends will be proportional to : (A) magnetic flux (B) total change of magnetic flux (C) (1/velocity of the rod) (D) (1/magnitude of the magnetic field)

Tardigrade Admin · Accepted Answer

E =- (d φ/dt) . So charge developed across the ends is determined by (d φ/dt) .But the current through it depends on the total change in flux

Q. A copper rod is moved in a magnetic field. The charge developed across its ends will be proportional to :

magnetic flux

total change of magnetic flux

$\frac{1}{v e l oc i t y o f t h e ro d}$

$\frac{1}{ma g ni t u d e o f t h e ma g n e t i c f i e l d}$

$E = - \frac{d ϕ}{d t}$ . So charge developed across the ends is determined by $\frac{d ϕ}{d t}$ .But the current through it depends on the total change in flux

Q. A copper rod is moved in a magnetic field. The charge developed across its ends will be proportional to :

magnetic flux

total change of magnetic flux

velocityoftherod1​

magnitudeofthemagneticfield1​

E=−dtdϕ​ . So charge developed across the ends is determined by dtdϕ​ .But the current through it depends on the total change in flux

$\frac{1}{v e l oc i t y o f t h e ro d}$

$\frac{1}{ma g ni t u d e o f t h e ma g n e t i c f i e l d}$

$E = - \frac{d ϕ}{d t}$ . So charge developed across the ends is determined by $\frac{d ϕ}{d t}$ .But the current through it depends on the total change in flux