A coordination complex compound of cobalt has the molecular formula containing five ammonia molecules, one nitro group and two chlorine atoms for one cobalt atom. One mole of this compound produces three mole ions in an aqueous solution; on reacting with excess of AgNO3, AgCl is precipitated. The ionic formula for this complex would be:

Question

A coordination complex compound of cobalt has the molecular formula containing five ammonia molecules, one nitro group and two chlorine atoms for one cobalt atom. One mole of this compound produces three mole ions in an aqueous solution; on reacting with excess of AgNO3, AgCl is precipitated. The ionic formula for this complex would be: (A) [Co(NH3)5(NO2)]Cl (B) [Co(NH3)5 Cl] [Cl(NO2)] (C) [Co(NH3)4 (NO2) Cl] [(NH3)Cl] (D) [Co(NH3)5] [(NO2)2Cl2]

Tardigrade Admin · Accepted Answer

The most probable complex which gives three mole ions in aqueous solution may be [Co (NH3)5 NO2] Cl2.

$[C o (N H_{3})_{5} (N O_{2})] Cl$

$[C o (N H_{3})_{5} Cl] [Cl (N O_{2})]$

$[C o (N H_{3})_{4} (N O_{2}) Cl] [(N H_{3}) Cl]$

$[C o (N H_{3})_{5}] [(N O_{2})_{2} C l_{2}]$

The most probable complex which gives three mole ions in aqueous solution may be $[C o (N H_{3})_{5} N O_{2}] C l_{2} .$

[Co(NH3​)5​(NO2​)]Cl

[Co(NH3​)5​Cl][Cl(NO2​)]

[Co(NH3​)4​(NO2​)Cl][(NH3​)Cl]

[Co(NH3​)5​][(NO2​)2​Cl2​]

The most probable complex which gives three mole ions in aqueous solution may be [Co(NH3​)5​NO2​]Cl2​.

$[C o (N H_{3})_{5} (N O_{2})] Cl$

$[C o (N H_{3})_{5} Cl] [Cl (N O_{2})]$

$[C o (N H_{3})_{4} (N O_{2}) Cl] [(N H_{3}) Cl]$

$[C o (N H_{3})_{5}] [(N O_{2})_{2} C l_{2}]$

The most probable complex which gives three mole ions in aqueous solution may be $[C o (N H_{3})_{5} N O_{2}] C l_{2} .$