Question

A container of volume V, contains 0.28 g of $N_2$ gas. If same volume of an unknown gas under similar conditions of temperature and pressure weighs 0.44g, the molecular mass of the gas is

• A. 22
• B. 44
• C. 66
• D. 88

Answer 1

Answer: (B)

Ratio of the masses of equal volumes of two gases under similar conditions is the same as the ratio of their molecular masses
Thus, $\frac{M_{\left(G\right)}}{M_{\left(N_2\right)}}=\frac{0.44}{0.28}$
$\therefore M_{\left(G\right)}=\frac{0.44}{0.28}\times 28$
$=44$